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Simplifying
12[(5x + 1)(5x + -1)] = 0
Reorder the terms:
12[(1 + 5x)(5x + -1)] = 0
Reorder the terms:
12[(1 + 5x)(-1 + 5x)] = 0
Multiply (1 + 5x) * (-1 + 5x)
12[(1(-1 + 5x) + 5x * (-1 + 5x))] = 0
12[((-1 * 1 + 5x * 1) + 5x * (-1 + 5x))] = 0
12[((-1 + 5x) + 5x * (-1 + 5x))] = 0
12[(-1 + 5x + (-1 * 5x + 5x * 5x))] = 0
12[(-1 + 5x + (-5x + 25x2))] = 0
Combine like terms: 5x + -5x = 0
12[(-1 + 0 + 25x2)] = 0
12[(-1 + 25x2)] = 0
[-1 * 12 + 25x2 * 12] = 0
[-12 + 300x2] = 0
Solving
-12 + 300x2 = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '12' to each side of the equation.
-12 + 12 + 300x2 = 0 + 12
Combine like terms: -12 + 12 = 0
0 + 300x2 = 0 + 12
300x2 = 0 + 12
Combine like terms: 0 + 12 = 12
300x2 = 12
Divide each side by '300'.
x2 = 0.04
Simplifying
x2 = 0.04
Take the square root of each side:
x = {-0.2, 0.2}
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